<?xml version='1.0' encoding='UTF-8'?><?xml-stylesheet href="http://www.blogger.com/styles/atom.css" type="text/css"?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:georss='http://www.georss.org/georss' xmlns:gd='http://schemas.google.com/g/2005' xmlns:thr='http://purl.org/syndication/thread/1.0'><id>tag:blogger.com,1999:blog-4915630045685458021</id><updated>2011-07-30T11:01:43.167-07:00</updated><category term='Quiz'/><title type='text'>W4HHH</title><subtitle type='html'>Quiz and testing resource for Ellijay Amateur Radio Society, Ellijay, GA. USA</subtitle><link rel='http://schemas.google.com/g/2005#feed' type='application/atom+xml' href='http://w4hhh.blogspot.com/feeds/posts/default'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4915630045685458021/posts/default?max-results=100'/><link rel='alternate' type='text/html' href='http://w4hhh.blogspot.com/'/><link rel='hub' href='http://pubsubhubbub.appspot.com/'/><author><name>W4HHH</name><uri>http://www.blogger.com/profile/10141341726071238206</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='32' src='http://1.bp.blogspot.com/_jxlyl304DIc/S3_zjCnLUpI/AAAAAAAAAAM/64AE3gLTMUE/s1600-R/earslogo.gif'/></author><generator version='7.00' uri='http://www.blogger.com'>Blogger</generator><openSearch:totalResults>4</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>100</openSearch:itemsPerPage><entry><id>tag:blogger.com,1999:blog-4915630045685458021.post-1813723241463228256</id><published>2010-03-06T18:00:00.000-08:00</published><updated>2010-03-06T18:08:15.719-08:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='Quiz'/><title type='text'>Ham Cram Quest Pool</title><content type='html'>&lt;span style="color: rgb(204, 0, 0);"&gt;1  The 7.250 MHz frequency is in the General Class portion of the 40-meter&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(204, 0, 0);"&gt;band. [97.301(d)]&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(204, 0, 0);"&gt;G1A05 (A) [97.301(d)]&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(204, 0, 0);"&gt;Which of the following frequencies is in the General Class portion of the 40 meter&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(204, 0, 0);"&gt;band?&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(204, 0, 0);"&gt;A. 7.250 MHz&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(204, 0, 0);"&gt;B. 7.500 MHz&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(204, 0, 0);"&gt;C. 40.200 MHz&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(204, 0, 0);"&gt;D. 40.500 MHz&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;2  Two hundred (200) feet is the maximum height above ground to which an&lt;br /&gt;antenna structure may be erected without requiring notification to the FAA&lt;br /&gt;and registration with the FCC, provided it is not at or near a public-use&lt;br /&gt;airport. [97.15(a)]&lt;br /&gt;G1B01 (C) [97.15(a)]&lt;br /&gt;What is the maximum height above ground to which an antenna structure may be erected&lt;br /&gt;without requiring notification to the FAA and registration with the FCC, provided it&lt;br /&gt;is not at or near a public-use airport?&lt;br /&gt;A. 50 feet&lt;br /&gt;B. 100 feet&lt;br /&gt;C. 200 feet&lt;br /&gt;D. 300 feet&lt;br /&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;3  In single sideband (SSB) voice mode, only one sideband is transmitted.&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;The other sideband and carrier are suppressed.&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;G2A07 (B)&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;Which of the following statements is true of the single sideband (SSB) voice mode?&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;A. Only one sideband and the carrier are transmitted; the other sideband is&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;suppressed&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;B. Only one sideband is transmitted; the other sideband and carrier are suppressed&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;C. SSB voice transmissions have higher average power than any other mode&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;D. SSB is the only mode that is authorized on the 160, 75 and 40 meter amateur bands&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;4  The minimum frequency separation between CW signals to minimize&lt;br /&gt;interference is 150 to 500 Hz.&lt;br /&gt;G2B04 (B)&lt;br /&gt;What minimum frequency separation between CW signals should be allowed to minimize&lt;br /&gt;interference?&lt;br /&gt;A. 5 to 50 Hz&lt;br /&gt;B. 150 to 500 Hz&lt;br /&gt;C. 1 to 3 kHz&lt;br /&gt;D. 3 to 6 kHz&lt;br /&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;5  The following information is traditionally contained in a station log:&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;o Date and time of contact&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;o Band and/or frequency of the contact&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;o Call sign of station contacted and the signal report given&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;[All of these choices are correct]&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;G2D09 (D)&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;What information is traditionally contained in a station log?&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;A. Date and time of contact&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;B. Band and/or frequency of the contact&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;C. Call sign of station contacted and the signal report given&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;D. All of these choices are correct&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;6  The most common frequency shift for RTTY emissions in the amateur HF bands is 170 Hz.&lt;br /&gt;G2E06 (B)&lt;br /&gt;What is the most common frequency shift for RTTY emissions in the amateur HF&lt;br /&gt;bands?&lt;br /&gt;A. 85 Hz&lt;br /&gt;B. 170 Hz&lt;br /&gt;C. 425 Hz&lt;br /&gt;D. 850 Hz&lt;br /&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;7  The F2 region be expected to reach its maximum height at your location at&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;noon during the summer&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;G3C02 (A)&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;When can the F2 region be expected to reach its maximum height at your location?&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;A. At noon during the summer&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;B. At midnight during the summer&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;C. At dusk in the spring and fall&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;D. At noon during the winter&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;8  Transmitter linearity performance is analyzed by a two-tone test.&lt;br /&gt;What type of transmitter performance does a two-tone test analyze?&lt;br /&gt;A. Linearity&lt;br /&gt;B. Carrier and undesired sideband suppression&lt;br /&gt;C. Percentage of frequency modulation&lt;br /&gt;D. Percentage of carrier phase shift&lt;br /&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;9  The RMS value measurement of an AC signal is equivalent to a DC voltage of the same value.&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;G5B07 (C)&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;Which measurement of an AC signal is equivalent to a DC voltage of the same value?&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;A. The peak-to-peak value&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;B. The peak value&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;C. The RMS value&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;D. The reciprocal of the RMS value&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;10  To increase the circuit resistance a resistor should be added in series in a circuit.&lt;br /&gt;Rtotal = R1+ R2+ R3+…&lt;br /&gt;G5C16 (B)&lt;br /&gt;What component should be added to an existing resistor in a circuit to increase&lt;br /&gt;circuit resistance?&lt;br /&gt;A. A resistor in parallel&lt;br /&gt;B. A resistor in series&lt;br /&gt;C. A capacitor in series&lt;br /&gt;D. A capacitor in parallel&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/4915630045685458021-1813723241463228256?l=w4hhh.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://w4hhh.blogspot.com/feeds/1813723241463228256/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://w4hhh.blogspot.com/2010/03/ham-cram-quest-pool.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4915630045685458021/posts/default/1813723241463228256'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4915630045685458021/posts/default/1813723241463228256'/><link rel='alternate' type='text/html' href='http://w4hhh.blogspot.com/2010/03/ham-cram-quest-pool.html' title='Ham Cram Quest Pool'/><author><name>KF4AWU</name><uri>http://www.blogger.com/profile/01738100338300420668</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='25' src='http://1.bp.blogspot.com/_xUvAbNwKsEg/S36bwJvA_2I/AAAAAAAAABQ/8LIqKJIwq2E/S220/davoid200.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4915630045685458021.post-2982313628833099889</id><published>2010-02-23T02:35:00.000-08:00</published><updated>2010-02-23T02:43:14.950-08:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='Quiz'/><title type='text'>This Monday Night's net quiz was a CW message.</title><content type='html'>&lt;div style="text-align: right;"&gt;&lt;span style="color: rgb(0, 0, 0);font-family:verdana;font-size:130%;"  &gt;&lt;span style="font-weight: bold;"&gt;Monday, February 22, 2010&lt;/span&gt;&lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(0, 0, 0);font-family:verdana;font-size:130%;"  &gt;&lt;span style="font-weight: bold;"&gt;&lt;/span&gt;&lt;/span&gt;&lt;/div&gt;&lt;br /&gt;&lt;span style="font-weight: bold;"&gt;....  .-  - -  / ..-.  .  ...  - /  .- - -  .. -   .-..  -.- - / ...- -   . - - - -&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;The quiz and answer is:  HAM               FEST                     JULY                       31&lt;br /&gt;&lt;br /&gt;73's&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/4915630045685458021-2982313628833099889?l=w4hhh.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://w4hhh.blogspot.com/feeds/2982313628833099889/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://w4hhh.blogspot.com/2010/02/this-monday-nights-net-quiz-was-cw.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4915630045685458021/posts/default/2982313628833099889'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4915630045685458021/posts/default/2982313628833099889'/><link rel='alternate' type='text/html' href='http://w4hhh.blogspot.com/2010/02/this-monday-nights-net-quiz-was-cw.html' title='This Monday Night&apos;s net quiz was a CW message.'/><author><name>KF4AWU</name><uri>http://www.blogger.com/profile/01738100338300420668</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='25' src='http://1.bp.blogspot.com/_xUvAbNwKsEg/S36bwJvA_2I/AAAAAAAAABQ/8LIqKJIwq2E/S220/davoid200.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4915630045685458021.post-2660815134970272144</id><published>2010-02-20T07:05:00.000-08:00</published><updated>2010-02-20T07:59:56.785-08:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='Quiz'/><title type='text'>EARS ON THE AIR QUIZ</title><content type='html'>&lt;div style="text-align: right;"&gt;&lt;span style="color: rgb(0, 0, 0);font-family:verdana;font-size:130%;"  &gt;&lt;span style="font-weight: bold;"&gt;Monday, February 15, 2010&lt;br /&gt;&lt;/span&gt;&lt;/span&gt;&lt;div style="text-align: center; font-weight: bold;"&gt;&lt;br /&gt;&lt;span style="color: rgb(0, 102, 0);"&gt;This quiz is based on the Propagation &lt;/span&gt;&lt;br /&gt;&lt;span style="color: rgb(0, 102, 0);"&gt;slide presentation made at the EARS February meeting.&lt;/span&gt;&lt;/div&gt;&lt;div style="text-align: left;"&gt;&lt;br /&gt;&lt;span style="font-weight: bold; color: rgb(153, 0, 0);"&gt;1.&lt;/span&gt;&lt;span style="color: rgb(153, 0, 0);"&gt; Effective radio communication results from which of these factors:&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;ul style="color: rgb(153, 0, 0);"&gt;&lt;li&gt;&lt;span style="font-weight: bold;"&gt;a.&lt;/span&gt;  Equipment&lt;/li&gt;&lt;li&gt;&lt;span style="font-weight: bold;"&gt;b.&lt;/span&gt;  Antenna System&lt;/li&gt;&lt;li&gt;&lt;span style="font-weight: bold;"&gt;c. &lt;/span&gt; Operating Skills&lt;br /&gt;&lt;/li&gt;&lt;li&gt;&lt;span style="font-weight: bold;"&gt;d.&lt;/span&gt;  All three&lt;/li&gt;&lt;/ul&gt;&lt;div style="text-align: center;"&gt;&lt;span style="font-weight: bold;"&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;Answer: d. All three&lt;/span&gt;&lt;br /&gt;&lt;/span&gt;&lt;div style="text-align: left;"&gt;&lt;span style="font-weight: bold;"&gt;_______________________________________________________&lt;br /&gt;2.&lt;/span&gt; What two types of energy fields make up a radio wave?&lt;br /&gt;&lt;br /&gt;&lt;div style="text-align: center;"&gt;&lt;span style="font-weight: bold;"&gt;Answer: Electric and Magnetic&lt;br /&gt;&lt;/span&gt;&lt;div style="text-align: left;"&gt;&lt;span style="font-weight: bold;"&gt;_______________________________________________________&lt;br /&gt;&lt;/span&gt;&lt;span style="font-weight: bold; color: rgb(153, 0, 0);"&gt;3.&lt;/span&gt;&lt;span style="color: rgb(153, 0, 0);"&gt; The polarization of a radio wave is determined by:&lt;/span&gt;&lt;br /&gt;&lt;div style="text-align: center;"&gt;&lt;span style="font-weight: bold; color: rgb(153, 0, 0);"&gt;Answer: The electric lines of force.&lt;/span&gt;&lt;br /&gt;&lt;/div&gt;&lt;span style="font-weight: bold;"&gt;_______________________________________________________&lt;br /&gt;&lt;/span&gt;&lt;span style="font-weight: bold;"&gt;4. &lt;/span&gt;The strength of a radio wave:&lt;br /&gt;&lt;ul&gt;&lt;li&gt;a. Increases as it spreads from the source.&lt;/li&gt;&lt;li&gt;b. Decreases as it spreads from the source.&lt;br /&gt;&lt;/li&gt;&lt;/ul&gt;&lt;div style="text-align: center;"&gt;&lt;span style="font-weight: bold;"&gt;Answer: b.&lt;/span&gt;&lt;br /&gt;&lt;/div&gt;&lt;span style="font-weight: bold;"&gt;_______________________________________________________&lt;br /&gt;&lt;/span&gt;&lt;span style="font-weight: bold; color: rgb(153, 0, 0);"&gt;5. &lt;/span&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;What are the two major phenomena affecting radio propagation?&lt;/span&gt;&lt;br /&gt;&lt;ol style="color: rgb(153, 0, 0);"&gt;&lt;li&gt; Reflection&lt;/li&gt;&lt;li&gt;Refraction&lt;/li&gt;&lt;li&gt;Isolation&lt;/li&gt;&lt;li&gt;Perturbations&lt;/li&gt;&lt;li&gt;Both 3 &amp;amp; 4&lt;/li&gt;&lt;li&gt;Both 2 &amp;amp; 3&lt;/li&gt;&lt;li&gt;Both 1 &amp;amp; 2&lt;/li&gt;&lt;/ol&gt;&lt;div style="text-align: center;"&gt;&lt;span style="font-weight: bold; color: rgb(153, 0, 0);"&gt;Answer: 7.&lt;/span&gt;&lt;br /&gt;&lt;/div&gt;&lt;span style="font-weight: bold;"&gt;_______________________________________________________&lt;br /&gt;&lt;/span&gt;&lt;span style="font-weight: bold;"&gt;6.&lt;/span&gt; Ground Waves…&lt;br /&gt;&lt;ul&gt;&lt;li&gt;a. Travel farther at lower frequencies&lt;/li&gt;&lt;li&gt;b. Travel farther at higher frequencies&lt;/li&gt;&lt;/ul&gt;&lt;div style="text-align: center;"&gt;&lt;span style="font-weight: bold;"&gt;Answer: a.&lt;/span&gt;&lt;br /&gt;&lt;/div&gt;&lt;span style="font-weight: bold;"&gt;_______________________________________________________&lt;br /&gt;&lt;/span&gt;&lt;span style="font-weight: bold; color: rgb(204, 0, 0);"&gt;7. &lt;/span&gt;&lt;span style="color: rgb(204, 0, 0);"&gt;The Ionosphere returns HF radio waves back from the transmitter to the earth at a distance called the:&lt;/span&gt;&lt;br /&gt;&lt;ul style="color: rgb(204, 0, 0);"&gt;&lt;li&gt;a. Critical Angle&lt;/li&gt;&lt;li&gt;b. Skip&lt;/li&gt;&lt;/ul&gt;&lt;div style="text-align: center;"&gt;&lt;span style="font-weight: bold; color: rgb(204, 0, 0);"&gt;Answer: b.&lt;/span&gt;&lt;br /&gt;&lt;/div&gt;&lt;span style="font-weight: bold;"&gt;_______________________________________________________&lt;br /&gt;&lt;/span&gt;&lt;span style="font-weight: bold;"&gt;8. &lt;/span&gt;There are four layers in the ionosphere: F1, F2, E and D. Which one normally remains in place after sunset?&lt;br /&gt;&lt;div style="text-align: center;"&gt;&lt;span style="font-weight: bold;"&gt;Answer: F1.&lt;/span&gt;&lt;br /&gt;&lt;/div&gt;&lt;span style="font-weight: bold;"&gt;_______________________________________________________&lt;br /&gt;&lt;/span&gt;&lt;span style="font-weight: bold; color: rgb(153, 0, 0);"&gt;9.&lt;/span&gt;&lt;span style="color: rgb(153, 0, 0);"&gt; At VHF and UHF frequencies, long distance transmission beyond Line-of-sight, is possible due to what phenomenon?&lt;/span&gt;&lt;br /&gt;&lt;div style="text-align: center;"&gt;&lt;span style="font-weight: bold; color: rgb(153, 0, 0);"&gt;Answer: Ducting &lt;/span&gt;&lt;br /&gt;&lt;/div&gt;&lt;/div&gt;&lt;/div&gt;&lt;span style="font-weight: bold;"&gt;&lt;/span&gt;&lt;/div&gt;&lt;/div&gt;&lt;/div&gt;&lt;/div&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/4915630045685458021-2660815134970272144?l=w4hhh.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://w4hhh.blogspot.com/feeds/2660815134970272144/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://w4hhh.blogspot.com/2010/02/ears-on-air-quiz.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4915630045685458021/posts/default/2660815134970272144'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4915630045685458021/posts/default/2660815134970272144'/><link rel='alternate' type='text/html' href='http://w4hhh.blogspot.com/2010/02/ears-on-air-quiz.html' title='EARS ON THE AIR QUIZ'/><author><name>W4HHH</name><uri>http://www.blogger.com/profile/10141341726071238206</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='32' src='http://1.bp.blogspot.com/_jxlyl304DIc/S3_zjCnLUpI/AAAAAAAAAAM/64AE3gLTMUE/s1600-R/earslogo.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4915630045685458021.post-1813428578641236541</id><published>2010-02-20T05:58:00.000-08:00</published><updated>2010-02-20T07:03:53.394-08:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='Quiz'/><title type='text'>EARS MONDAY NIGHT NET TECHNICAL QUIZ</title><content type='html'>&lt;div style="text-align: right;"&gt;&lt;span style="font-size:130%;"&gt;&lt;span style="font-weight: bold;font-family:verdana;" &gt;February 8, 2010&lt;br /&gt;&lt;/span&gt;&lt;/span&gt;&lt;div style="text-align: left;"&gt;&lt;br /&gt;&lt;span style="font-weight: bold; color: rgb(102, 0, 0);"&gt;1.&lt;/span&gt;&lt;span style="color: rgb(102, 0, 0);"&gt; You need a 50 Ohm, 1 Watt resistor in a circuit you are constructing. You don't have one but in your junk box you find 3 resistors: A 100 Ohm, 1 Watt Resistor, a 50 Ohm, ½ Watt Resistor and a 100 Ohm, 2 Watt Resistor. Which two resistors would you need to use in combination to meet your resistor need?&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;ul style="color: rgb(102, 0, 0);"&gt;&lt;li&gt;&lt;span style="font-weight: bold;"&gt;a.&lt;/span&gt;     100 Ohm 1 Watt and 50 Ohm ½ Watt &lt;/li&gt;&lt;li&gt;&lt;span style="font-weight: bold;"&gt;b. &lt;/span&gt;    100 Ohm 2 Watt and 50 Ohm ½ Watt&lt;/li&gt;&lt;li&gt;&lt;span style="font-weight: bold;"&gt;c.&lt;/span&gt;      100 Ohm 1 Watt and 100 Ohm 2 Watt&lt;/li&gt;&lt;/ul&gt;&lt;div style="text-align: right; color: rgb(102, 0, 0);"&gt;&lt;blockquote&gt;&lt;div style="text-align: left;"&gt;&lt;strong&gt;The answer is c.&lt;/strong&gt; Two main things to consider with this question: First, how to calculate the total resistance needed and Second the wattage of the resistor. The total resistance is where Question 2 below comes in. As to the wattage, if you need a 1 watt resistor, you wouldn't want to use a ½ watt resistor in this particular case. So you could eliminate the answers with 1/2 watt in them right away. That would make the right answer c.&lt;/div&gt;&lt;/blockquote&gt;&lt;/div&gt;&lt;/div&gt;&lt;/div&gt;&lt;span style="font-weight: bold;"&gt;_____________________________________________________________&lt;br /&gt;&lt;span style="color: rgb(0, 0, 0);"&gt;2.&lt;/span&gt;&lt;/span&gt;&lt;span style="color: rgb(0, 0, 0);"&gt; In Question 1, how would you connect the two resistors?&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;ul style="color: rgb(0, 0, 0);"&gt;&lt;li&gt;&lt;span style="font-weight: bold;"&gt;a.&lt;/span&gt;     In Parallel&lt;/li&gt;&lt;li&gt;&lt;span style="font-weight: bold;"&gt;b.    &lt;/span&gt; In Series&lt;/li&gt;&lt;/ul&gt;&lt;strong style="color: rgb(0, 0, 0);"&gt;&lt;/strong&gt;&lt;strong style="color: rgb(0, 0, 0);"&gt;&lt;/strong&gt;&lt;div style="text-align: left;"&gt;&lt;blockquote style="color: rgb(0, 0, 0);"&gt;&lt;strong&gt;The answer is a.&lt;/strong&gt; The general rule for resistances is, resistors in series ADD their resistances and resistors in parallel DIVIDE their resistances. Since a 50 Ohm resistor is needed, the two 100 Ohm resistors in series would add up to 200 Ohms. Not what you want. So, the answer must be (a) Parallel. By the way, the formula for figuring the final value of two resistors in parallel is as follows. First, lets name one resistor R1 and the other R2. The formula is, R1 times R2 divided by R1 plus R2. In this case R1 = 100 Ohms and R2 = 100 Ohms. So R1 times R2 (100 x 100) equals 10,000. Next R1 plus R2 (100 + 100) equals 200. Finally, divide 10,000 by 200 and you get 50 Ohms.&lt;/blockquote&gt;&lt;/div&gt;&lt;span style="font-weight: bold;"&gt;_____________________________________________________________&lt;br /&gt;&lt;/span&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;&lt;span style="font-weight: bold;"&gt;3&lt;/span&gt;. What is the formula most hams use for calculating the length of a dipole antenna?&lt;br /&gt;&lt;/span&gt;&lt;ul style="color: rgb(153, 0, 0);"&gt;&lt;li&gt;&lt;span style="font-weight: bold;"&gt;a.&lt;/span&gt;   Length = 2.68 times Height &lt;/li&gt;&lt;li&gt;&lt;span style="font-weight: bold;"&gt;b.&lt;/span&gt;   Length = 468 divided by Frequency in megaHertz&lt;/li&gt;&lt;li&gt;&lt;span style="font-weight: bold;"&gt;c.&lt;/span&gt;   Length = MC2&lt;/li&gt;&lt;li&gt;&lt;span style="font-weight: bold;"&gt;d.   &lt;/span&gt;Length = Base times Height.&lt;/li&gt;&lt;/ul&gt;&lt;strong style="color: rgb(153, 0, 0);"&gt;&lt;/strong&gt;&lt;div style="text-align: center;"&gt;&lt;strong style="color: rgb(153, 0, 0);"&gt;&lt;blockquote&gt;The answer is b.&lt;/blockquote&gt;&lt;/strong&gt;&lt;/div&gt;&lt;strong style="color: rgb(153, 0, 0);"&gt;&lt;/strong&gt;&lt;span style="font-weight: bold;"&gt;_____________________________________________________________&lt;br /&gt;&lt;/span&gt;&lt;span style="font-weight: bold;"&gt;4.&lt;/span&gt; Using the formula in Question 3, what is the approximate length of a half-wave dipole antenna to be used at 14.200 MHz?&lt;br /&gt;&lt;ul&gt;&lt;li&gt;&lt;span style="font-weight: bold;"&gt;a.&lt;/span&gt;    33 feet&lt;/li&gt;&lt;li&gt;&lt;span style="font-weight: bold;"&gt;b.&lt;/span&gt;    66 feet&lt;/li&gt;&lt;li&gt;&lt;span style="font-weight: bold;"&gt;c.&lt;/span&gt;    132 feet&lt;/li&gt;&lt;li&gt;&lt;span style="font-weight: bold;"&gt;d.&lt;/span&gt;    16.5 feet&lt;/li&gt;&lt;/ul&gt;&lt;div style="text-align: right;"&gt;&lt;strong&gt;&lt;/strong&gt;&lt;blockquote&gt;&lt;strong&gt;The answer is a.&lt;/strong&gt; 468 divided by 14.200 = 32.9 feet or 33 feet rounded.&lt;br /&gt;&lt;/blockquote&gt;&lt;/div&gt;&lt;span style="font-weight: bold;"&gt;_____________________________________________________________&lt;br /&gt;&lt;/span&gt;&lt;span style="color: rgb(153, 0, 0);"&gt;&lt;span style="font-weight: bold;"&gt;5.&lt;/span&gt; In NET Operation, who decides how the net will be conducted?&lt;/span&gt;&lt;br /&gt;&lt;br /&gt;&lt;ul style="color: rgb(153, 0, 0);"&gt;&lt;li&gt;&lt;span style="font-weight: bold;"&gt;a.&lt;/span&gt;    The highest class licensee that checks into the net&lt;/li&gt;&lt;li&gt;&lt;span style="font-weight: bold;"&gt;b.&lt;/span&gt;    The first ham to check into the net&lt;/li&gt;&lt;li&gt;&lt;span style="font-weight: bold;"&gt;c.&lt;/span&gt;    The NET control operator&lt;/li&gt;&lt;li&gt;&lt;span style="font-weight: bold;"&gt;d.&lt;/span&gt;    The ARRL Section Manager&lt;/li&gt;&lt;/ul&gt;&lt;div style="text-align: center; color: rgb(153, 0, 0);"&gt;&lt;strong&gt;The answer is c.&lt;/strong&gt;&lt;/div&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/4915630045685458021-1813428578641236541?l=w4hhh.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://w4hhh.blogspot.com/feeds/1813428578641236541/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://w4hhh.blogspot.com/2010/02/ears-monday-night-net-technical-quiz.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4915630045685458021/posts/default/1813428578641236541'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4915630045685458021/posts/default/1813428578641236541'/><link rel='alternate' type='text/html' href='http://w4hhh.blogspot.com/2010/02/ears-monday-night-net-technical-quiz.html' title='EARS MONDAY NIGHT NET TECHNICAL QUIZ'/><author><name>W4HHH</name><uri>http://www.blogger.com/profile/10141341726071238206</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='32' src='http://1.bp.blogspot.com/_jxlyl304DIc/S3_zjCnLUpI/AAAAAAAAAAM/64AE3gLTMUE/s1600-R/earslogo.gif'/></author><thr:total>0</thr:total></entry></feed>
